Lights will guide you home and ignite your bones.
And, I will try to fix you.
Are you sure you don't mean "1" to infinity? Because indexing things from "i" to infinity doesn't make any sense. If it's just 1 to infinity, then that's just the geometeric series (a + ar + ar^2 + ar^3 +...) - 1 where a=1 and r=1/2. In this case the sum is 1/(1-r) - 1, or 1/(1/2) - 1 = 2 - 1 = 1.If "i" was supposed to be some finite number, in which case you just want to find the sum from that point onwards, then you'd take 1 and subtract the partial sum from 1 to i-1 (or even easier, start with 2 and subtract the sum from 0 to i-1). This other sum would just be another geometric series, albeit a finite one. So the answer would be 2 - (1 - (1/2)^i)/(1 - 1/2), or 2 - 2(1 - (1/2)^i).
I'm assuming that "i" is an imaginary number (i.e. the negative power of 2). If n=0 we've figured that the solution is a number that approaches 2. We cannot figure how this operation changes when the low range is "i".
Ummm Kevin.. my head hurts just from looking at it...LOLHope you figure it outFinally had time during my trip to do a little "walk around the blogs"
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